How do I solve?
Apr 9th, 2009 Posted in Uncategorized |- Solve 4(y+3)=6
4(y+3) = 6 –> 4y+12 = 6 –> 4y=-6 –> y = -6/4 = -1 1/2
or
First divide each side by 4:
(y+3) = 6/4
Now subtract 3 from each side:
y = -6/4 +3
y = -6/4 + 12/4
y = 6/4 = 3/2 - Solve 2/3q + 5 = 3/4
subtract 5 from both sides of the = sign, then divide both sides by 2/32/3q + 5 = 3/4
2/3q + 5 - 5 = 3/4 - 5
2/3q = -17/4
2/3q (3/2) = (-17/4)(3/2)
q = -51/8 - Find the new number produced when the given number is increased or decreased by the given percent.
250: 63% decreases
1.
Calculate 250 x (1 - 63 %) = 250 x 37 % = 92.5or2.
% remaining is 100 - 63 = 37
so 37% is 37/100
37% of 250 = 250 x 37 / 100 = 92.5 - Write the equation for the line tangent to the circle x^2 + y^2 = 29, at (2, 5)
1. use implicit differentiation.
Differentiate with respect to x.2x + 2y(dy/dx) = 0
2. Next, solve for dy/dx.
2y(dy/dx) = -2x
dy/dx = (-2x)/(2y)
dy/dx = -x/y
The slope at (2, 5) can be found by setting x = 2 and y = 5. Use them to represent the slope.m = -2/5
Wwe have the slope, find the equation of the line with slope m = -2/5 and through (2, 5).
Using the slope formula,
(y2 - y1)/(x2 - x1) = m
Let (x1, y1) = (2, 5) (our given point)
(x2, y2) = (x, y) (our general point)
m = -2/5 (our evaluated slope.(y - 5)/(x - 2) = (-2/5)
Put in slope intercept form.
y - 5 = (-2/5)(x - 2)
y - 5 = (-2/5)x + (4/5)
y = (-2/5)x + (4/5) + 5
y = (-2/5)x + (4/5) + (25/5)
y = (-2/5)x + (29/5)
