Solve 4(y+3)=6
Apr 9th, 2009 Posted in Basic math | no comment »4(y+3) = 6 –> 4y+12 = 6 –> 4y=-6 –> y = -6/4 = -1 1/2
or
first divide each side by 4:
(y+3) = 6/4
Now subtract 3 from each side:
y = -6/4 +3
y = -6/4 + 12/4
y = 6/4 = 3/2
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